The angle of elevation of an object on a hill is observed from a certain point in the horizontal plane through its base to be $30^{\circ}$. After walking $120 \ m$ towards it on level ground, the angle of elevation is found to be $60^{\circ}$. Then the height of the object (in metres) is:

  • A
    $120$
  • B
    $60 \sqrt{3}$
  • C
    $120 \sqrt{3}$
  • D
    $60$

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