The angular resolution of a 10,cm diameter te | vedclass

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Question

(B) The angular resolution $\Delta 	heta$ of a telescope is given by the formula: $\Delta 	heta = \frac{1.22 \lambda}{D}$.Given:Diameter of the tele

Vedclass · Accepted Answer

$10^{-5}\,	ext{rad}$

Vedclass · Answer

(B) The angular resolution $\Delta 	heta$ of a telescope is given by the formula: $\Delta 	heta = \frac{1.22 \lambda}{D}$.Given:Diameter of the telescope,$D = 10\,cm = 0.1\,m$.Wavelength,$\lambda = 5000\,\mathring{A} = 5000 	imes 10^{-10}\,m = 5 	imes 10^{-7}\,m$.Substituting the values into the formula:$\Delta 	heta = \frac{1.22 	imes 5 	imes 10^{-7}}{0.1}$.$\Delta 	heta = 1.22 	imes 5 	imes 10^{-6}$.$\Delta 	heta = 6.1 	imes 10^{-6}\,	ext{rad}$.This value is of the order of $10^{-5}\,	ext{rad}$.

The angular resolution of a $10\,cm$ diameter telescope at a wavelength of $5000\,\mathring{A}$ is of the order of:

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