The approximate value of the mean deviation a | vedclass

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(D) First,we find the midpoints $(y_i)$ of the class intervals: $y_i$$1$$3$$5$$7$$9$$f_i$$1$$2$$3$$2$$1$ The mean $\bar{y}$ is calculated as: $\bar{y}

Vedclass · Accepted Answer

$1.78$

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(D) First,we find the midpoints $(y_i)$ of the class intervals: $y_i$$1$$3$$5$$7$$9$$f_i$$1$$2$$3$$2$$1$ The mean $\bar{y}$ is calculated as: $\bar{y} = \frac{\sum f_i y_i}{\sum f_i} = \frac{(1 	imes 1) + (2 	imes 3) + (3 	imes 5) + (2 	imes 7) + (1 	imes 9)}{1+2+3+2+1} = \frac{1+6+15+14+9}{9} = \frac{45}{9} = 5$ The mean deviation about the mean is given by: $	ext{Mean Deviation} = \frac{\sum f_i |y_i - \bar{y}|}{\sum f_i} = \frac{1|1-5| + 2|3-5| + 3|5-5| + 2|7-5| + 1|9-5|}{9}$ $= \frac{1(4) + 2(2) + 3(0) + 2(2) + 1(4)}{9} = \frac{4+4+0+4+4}{9} = \frac{16}{9} \approx 1.78$

Class Interval	$0-2$	$2-4$	$4-6$	$6-8$	$8-10$
Frequency	$1$	$2$	$3$	$2$	$1$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Freq	$6$	$7$	$15$	$16$	$4$	$2$

The approximate value of the mean deviation about the mean for the following data is
Class Interval $0-2$ $2-4$ $4-6$ $6-8$ $8-10$
Frequency $1$ $2$ $3$ $2$ $1$

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The approximate value of the mean deviation about the mean for the following data is Class Interval$0-2$$2-4$$4-6$$6-8$$8-10$Frequency$1$$2$$3$$2$$1$