The area of a square is 196 , cm^2. Its side | vedclass

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(C) Area of the square $= a^2 = 196 \, cm^2$.Therefore,the side $a = \sqrt{196} = 14 \, cm$.Given that the side of the square is half the radius $(r)$

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$180$

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(C) Area of the square $= a^2 = 196 \, cm^2$.Therefore,the side $a = \sqrt{196} = 14 \, cm$.Given that the side of the square is half the radius $(r)$ of the circle,so $a = r/2$.Therefore,$r = 2 	imes a = 2 	imes 14 = 28 \, cm$.The circumference of the circle $= 2 \pi r = 2 	imes (22/7) 	imes 28 = 176 \, cm$.According to the question,the breadth $(b)$ of the rectangle is equal to the circumference of the circle,so $b = 176 \, cm$.The perimeter of the rectangle is given as $2(l + b) = 712 \, cm$.Substituting the value of $b$: $2(l + 176) = 712$.Dividing by $2$: $l + 176 = 356$.Therefore,$l = 356 - 176 = 180 \, cm$.

The area of a square is $196 \, cm^2$. Its side is half the radius of a circle. The circumference of the circle is equal to the breadth of a rectangle. If the perimeter of the rectangle is $712 \, cm$,what is the length of the rectangle? (in $cm$)

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