The area of the region bounded by $y^{2}=8x$ and $y^{2}=16(3-x)$ is equal to

  • A
    $\frac{32}{3}$
  • B
    $\frac{40}{3}$
  • C
    $16$
  • D
    $19$

Explore More

Similar Questions

The area (in square units) of the region enclosed by the ellipse $x^2+3y^2=18$ in the first quadrant below the line $y=x$ is:

The sine and cosine curves intersect infinitely many times,creating bounded regions of equal areas. The area of one such region is

Area of the region (in sq units) bounded by the curves $y=\sqrt{x}$, $x=\sqrt{y}$ and the lines $x=1$, $x=4$ is

Let $S$ be the region bounded by the curves $y=x^{3}$ and $y^{2}=x$. The curve $y=2|x|$ divides $S$ into two regions of areas $R_{1}$ and $R_{2}$. If $\max \{R_{1}, R_{2}\}=R_{2}$,then $\frac{R_{2}}{R_{1}}$ is equal to

The area (in sq. units) of the region lying in the first quadrant and enclosed by the $X$-axis,the straight line $x - \sqrt{3}y = 0$ and the circle $x^2 + y^2 = 4$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo