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(B) The bookshop has $10$ dozen chemistry books,$8$ dozen physics books,and $10$ dozen economics books. Since $1$ dozen $= 12$ books,the total number

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$20160$

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(B) The bookshop has $10$ dozen chemistry books,$8$ dozen physics books,and $10$ dozen economics books. Since $1$ dozen $= 12$ books,the total number of books are $120$ chemistry books,$96$ physics books,and $120$ economics books.The selling prices of a chemistry book,a physics book,and an economics book are Rs. $80$,Rs. $60$,and Rs. $40$ respectively.Representing the quantity as a row matrix $A$ and the price as a column matrix $B$:$A = [120 \quad 96 \quad 120]$$B = \begin{bmatrix} 80 \ 60 \ 40 \end{bmatrix}$The total amount is given by the product $AB$:$Total = [120 \quad 96 \quad 120] \begin{bmatrix} 80 \ 60 \ 40 \end{bmatrix}$$= (120 	imes 80) + (96 	imes 60) + (120 	imes 40)$$= 9600 + 5760 + 4800$$= 20160$Thus,the bookshop will receive Rs. $20160$ from the sale of all these books.

The bookshop of a particular school has $10$ dozen chemistry books,$8$ dozen physics books,and $10$ dozen economics books. Their selling prices are Rs. $80$,Rs. $60$,and Rs. $40$ each respectively. Find the total amount the bookshop will receive from selling all the books using matrix algebra.

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