The centre of the circle given by the paramet | vedclass

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(B) The given parametric equations are $x = 2 + 3\cos 	heta$ and $y = 3\sin 	heta - 1$.Rearranging these equations to isolate the trigonometric term

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$(2, -1)$

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(B) The given parametric equations are $x = 2 + 3\cos 	heta$ and $y = 3\sin 	heta - 1$.Rearranging these equations to isolate the trigonometric terms:$x - 2 = 3\cos 	heta \implies \cos 	heta = \frac{x - 2}{3}$$y + 1 = 3\sin 	heta \implies \sin 	heta = \frac{y + 1}{3}$Using the identity $\sin^2 	heta + \cos^2 	heta = 1$,we substitute the expressions:$(\frac{y + 1}{3})^2 + (\frac{x - 2}{3})^2 = 1$$(x - 2)^2 + (y + 1)^2 = 3^2$This is the standard form of a circle equation $(x - h)^2 + (y - k)^2 = r^2$,where $(h, k)$ is the centre.Comparing the equations,the centre $(h, k)$ is $(2, -1)$.

The centre of the circle given by the parametric equations $x = 2 + 3\cos \theta$ and $y = 3\sin \theta - 1$ is

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