The circumcentre of the triangle formed by th | vedclass

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(B) The given lines are $x = -2$,$y = -2$,and $x + y + 2 = 0$.$1$. Intersection of $x = -2$ and $y = -2$ is $A(-2, -2)$.$2$. Intersection of $x = -2$

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$(-1, -1)$

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(B) The given lines are $x = -2$,$y = -2$,and $x + y + 2 = 0$.$1$. Intersection of $x = -2$ and $y = -2$ is $A(-2, -2)$.$2$. Intersection of $x = -2$ and $x + y + 2 = 0$ is $B(-2, 0)$.$3$. Intersection of $y = -2$ and $x + y + 2 = 0$ is $C(0, -2)$.The triangle formed is a right-angled triangle at vertex $A(-2, -2)$ because the lines $x = -2$ and $y = -2$ are perpendicular.For a right-angled triangle,the circumcentre is the midpoint of the hypotenuse $BC$.Midpoint of $BC = \left( \frac{-2 + 0}{2}, \frac{0 + (-2)}{2} \right) = (-1, -1)$.

The circumcentre of the triangle formed by the lines $x = -2$,$y = -2$ and $x + y + 2 = 0$ is

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