The concentration of NaOH solution is 10^{-8} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a very dilute solution of a strong base like $NaOH$ with concentration $10^{-8} \ M$,the contribution of $[OH^{-}]$ from the auto-ionization o

Vedclass · Accepted Answer

Lies between $10^{-6} \ M$ and $10^{-7} \ M$

Vedclass · Answer

(D) For a very dilute solution of a strong base like $NaOH$ with concentration $10^{-8} \ M$,the contribution of $[OH^{-}]$ from the auto-ionization of water cannot be neglected.$H_2O ightleftharpoons H^{+} + OH^{-}$,where $[OH^{-}]_{water} = 10^{-7} \ M$.The total concentration of $[OH^{-}]$ is the sum of $[OH^{-}]$ from $NaOH$ $(10^{-8} \ M)$ and $[OH^{-}]$ from water $(10^{-7} \ M)$.$[OH^{-}]_{total} = [OH^{-}]_{NaOH} + [OH^{-}]_{water} = 10^{-8} + 10^{-7} = 10^{-8} + 10 	imes 10^{-8} = 11 	imes 10^{-8} = 1.1 	imes 10^{-7} \ M$.This value is slightly greater than $10^{-7} \ M$ but significantly less than $10^{-6} \ M$.However,considering the options provided,the concentration is effectively dominated by the water contribution,making it closer to $10^{-7} \ M$. Given the options,the most accurate description is that it lies between $10^{-6} \ M$ and $10^{-7} \ M$.

The concentration of $NaOH$ solution is $10^{-8} \ M$. Find out the $[OH^{-}]$ concentration.

Similar Questions

The $pH$ values of $(i) \ 0.1 \ M \ HCl_{(aq)}$,$(ii) \ 0.1 \ M \ KOH$,$(iii)$ tomato juice,and $(iv)$ pure water follow the order.

What is the normality of an aqueous solution of $H_2SO_4$ having $pH = 1$ (in $N$)?

$1 \, mL$ of $0.1 \, M$ $HCl$ is added to $999 \, mL$ of $0.1 \, N$ $NaCl$ solution. The $pH$ of the resulting solution will be:

What is the $pH$ value for $\frac{N}{10} \ H_2SO_4$?

What is the $pH$ of a $2.6 \times 10^{-8} \ M \ H^{+}$ ion solution?
$(\log 2.6 = 0.4150)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module