The coordinates of the focus of the parabola $(x+3)^2 = 2(y-5)$ are

$A = (-2, 0)$ and $P$ is a point on the parabola $y^2 = 8x$. If $Q$ bisects $\overline{AP}$ and the locus of $Q$ is a parabola,then its focus is

What is the point of intersection of the latus rectum and the axis of the parabola $y^2 - 4y - 2x - 8 = 0$?

Let $M$ be the foot of the perpendicular from a point $P$ on the parabola $y^2=8(x-3)$ onto its directrix and let $S$ be the focus of the parabola. If $\triangle SPM$ is an equilateral triangle,then $P$ is equal to

The point of intersection of tangents at the ends of the latus rectum of the parabola $y^2 = 4x$ is

If $x = my + c$ is a normal to the parabola ${x^2} = 4ay$,then the value of $c$ is