The correct order of bond enthalpy of given m | vedclass

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(D) The bond enthalpy depends on the bond order and bond length. The bond orders for $H_2$,$O_2$,and $N_2$ are $1$,$2$,and $3$ respectively.As the bon

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$H_2 < O_2 < N_2$

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(D) The bond enthalpy depends on the bond order and bond length. The bond orders for $H_2$,$O_2$,and $N_2$ are $1$,$2$,and $3$ respectively.As the bond order increases,the bond strength increases,and consequently,the bond enthalpy increases.The bond types are $H-H$ (single bond),$O=O$ (double bond),and $N \equiv N$ (triple bond).Therefore,the correct order of bond enthalpy is $H_2 < O_2 < N_2$.

The correct order of bond enthalpy of given molecules is

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