The correct order of decreasing third ionisat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The third ionisation enthalpy $(IE_3)$ corresponds to the energy required to remove an electron from the $M^{2+}$ ion.The electronic configuration

Vedclass · Accepted Answer

$Mn > Cr > V > Ti$

Vedclass · Answer

(A) The third ionisation enthalpy $(IE_3)$ corresponds to the energy required to remove an electron from the $M^{2+}$ ion.The electronic configurations of $M^{2+}$ ions are:$Ti^{2+} ([Ar] 3d^2)$$V^{2+} ([Ar] 3d^3)$$Cr^{2+} ([Ar] 3d^4)$$Mn^{2+} ([Ar] 3d^5)$Removing an electron from $Mn^{2+}$ $(3d^5)$ is difficult due to the stable half-filled $d$-orbital configuration.Removing an electron from $Cr^{2+}$ $(3d^4)$ is relatively easier than $Mn^{2+}$,but $Cr^{2+}$ has a higher $IE_3$ than $V^{2+}$ and $Ti^{2+}$ due to the exchange energy and stability factors.The correct order of decreasing $IE_3$ is $Mn > Cr > V > Ti$.

The correct order of decreasing third ionisation enthalpy of $Ti$,$V$,$Cr$,and $Mn$ is:

Similar Questions

The transition metal which shows oxidation states from $+2$ to $+7$ belongs to group:

Arrange the following ions in the increasing order of their magnetic moments: $(i) \, V^{4+}$,$(ii) \, Mn^{4+}$,$(iii) \, Fe^{3+}$,$(iv) \, Ni^{2+}$. $[V = 23, Mn = 25, Fe = 26, Ni = 28]$

Which of the following oxides is white but becomes yellow on heating?

What is the correct order of spin only magnetic moment (in $BM$) of $Mn^{2+}, Cr^{2+}$ and $V^{2+}$?

Which transition metal configuration exhibits the highest oxidation state?

Vedclass Test Series

Exam Paper Generator

Online Exam Module