The correct order of the relative stability o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of carbanions is determined by factors such as resonance,hybridization,and inductive effects.$IV$. $(C_6H_5)_2CH^{-}$: This carbanio

Vedclass · Accepted Answer

$IV > II > I > III$

Vedclass · Answer

(C) The stability of carbanions is determined by factors such as resonance,hybridization,and inductive effects.$IV$. $(C_6H_5)_2CH^{-}$: This carbanion is highly stable due to extensive resonance with two phenyl rings and the delocalization of the negative charge.$II$. $CH_2=CH-CH_2^{-}$: This is an allylic carbanion,which is stabilized by resonance (conjugation of the negative charge with the double bond).$I$. $HC \equiv C^{-}$: This is an $sp$-hybridized carbanion. The higher $s$-character $(50\%)$ makes the carbon more electronegative,thus stabilizing the negative charge.$III$. $H_2C=CH^{-}$: This is an $sp^2$-hybridized carbanion. It has less $s$-character $(33.3\%)$ compared to the $sp$-hybridized carbanion,making it less stable than $I$.Comparing these,the order of stability is $IV > II > I > III$.

The correct order of the relative stability of the following carbanions is:
$I$. $HC \equiv C^{-}$
$II$. $CH_2=CH-CH_2^{-}$
$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$

Similar Questions

In which of the following pairs is $A$ more stable than $B$?
$A$ $B$

The reaction of methyltrichloroacetate $(Cl_{3}CCO_{2}Me)$ with sodium methoxide $(NaOMe)$ generates

What is the shape of the methyl carbocation,$\overset{\oplus}{C}H_3$?

Taking into account the stability of various carbocations and the rules governing mechanisms of carbocation rearrangements,which reaction is most likely to occur during the given reaction?

The most stable carbanion among the following is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of the relative stability of the following carbanions is:$I$. $HC \equiv C^{-}$$II$. $CH_2=CH-CH_2^{-}$$III$. $H_2C=CH^{-}$$IV$. $(C_6H_5)_2CH^{-}$