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(B) Let the two numbers be $x$ and $y$,where $x > y$.According to the problem:$x - y = 9$  ---(Equation $1$)$x^2 - y^2 = 207$  ---(Equation $2$)We kno

Vedclass · Accepted Answer

$16$ and $7$

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(B) Let the two numbers be $x$ and $y$,where $x > y$.According to the problem:$x - y = 9$  ---(Equation $1$)$x^2 - y^2 = 207$  ---(Equation $2$)We know that $x^2 - y^2 = (x + y)(x - y)$.Substituting the values from Equation $1$ into Equation $2$:$(x + y)(9) = 207$$x + y = 207 / 9 = 23$  ---(Equation $3$)Now,add Equation $1$ and Equation $3$:$(x - y) + (x + y) = 9 + 23$$2x = 32$$x = 16$Substitute $x = 16$ into Equation $1$:$16 - y = 9$$y = 16 - 9 = 7$Therefore,the numbers are $16$ and $7$.

The difference between two numbers is $9$ and the difference between their squares is $207$. The numbers are

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