The domain of the function y = frac{1}{sqrt{| | vedclass

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Question

(A) For the function $y = \frac{1}{\sqrt{|x| - x}}$ to be defined,the expression inside the square root must be strictly positive:$|x| - x > 0$$|x| >

Vedclass · Accepted Answer

$( - \infty, 0)$

Vedclass · Answer

(A) For the function $y = \frac{1}{\sqrt{|x| - x}}$ to be defined,the expression inside the square root must be strictly positive:$|x| - x > 0$$|x| > x$We know that by definition of the absolute value function:If $x \ge 0$,then $|x| = x$,which implies $x > x$,which is impossible.If $x  x$,or $0 > 2x$,which simplifies to $x Therefore,the function is defined for all $x The domain is $( - \infty, 0)$.

The domain of the function $y = \frac{1}{\sqrt{|x| - x}}$ is

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