The electronic spectrum of [Ti(H_2O)_6]^{3+} | vedclass

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(D) The complex $[Ti(H_2O)_6]^{3+}$ contains $Ti^{3+}$ which has a $d^1$ electronic configuration.In an octahedral field,the $d^1$ electron occupies t

Vedclass · Accepted Answer

$97$

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(D) The complex $[Ti(H_2O)_6]^{3+}$ contains $Ti^{3+}$ which has a $d^1$ electronic configuration.In an octahedral field,the $d^1$ electron occupies the $t_{2g}$ orbital.The energy difference between $t_{2g}$ and $e_g$ orbitals is $\Delta_0 = 20,300 \, cm^{-1}$.The $CFSE$ for a $d^1$ configuration is given by $0.4 \Delta_0$.$CFSE = 0.4 	imes 20,300 \, cm^{-1} = 8,120 \, cm^{-1}$.To convert $cm^{-1}$ to $kJ \, mol^{-1}$,we use the conversion factor $1 \, kJ \, mol^{-1} \approx 83.7 \, cm^{-1}$.$CFSE = \frac{8,120}{83.7} \approx 97 \, kJ \, mol^{-1}$.

The electronic spectrum of $[Ti(H_2O)_6]^{3+}$ shows a single broad peak with a maximum at $20,300 \, cm^{-1}$. The crystal field stabilization energy $(CFSE)$ of the complex ion,in $kJ \, mol^{-1}$,is :

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