The ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ $(b>a)$ and the parabola $y^2=4ax$ intersect at right angles. If $e$ is the eccentricity of the ellipse,then $2e^2=$

  • A
    $1$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{8}$
  • D
    $\frac{1}{3}$

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