The energy of an electron in the 3^{rd} orbit | vedclass

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(B) The energy of an electron in the $n^{th}$ orbit of an $H$-like atom is given by the formula: $E_{n} = \frac{-13.6 	imes Z^2}{n^2} \ eV$. For the

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$-2.42 	imes 10^{-19}$

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(B) The energy of an electron in the $n^{th}$ orbit of an $H$-like atom is given by the formula: $E_{n} = \frac{-13.6 	imes Z^2}{n^2} \ eV$. For the $H$-atom, $Z = 1$ and for the $3^{rd}$ orbit, $n = 3$. Substituting these values: $E = \frac{-13.6 	imes (1)^2}{(3)^2} \ eV = \frac{-13.6}{9} \ eV \approx -1.511 \ eV$. Since $1 \ eV = 1.602 	imes 10^{-19} \ J$,$E = -1.511 	imes 1.602 	imes 10^{-19} \ J \approx -2.42 	imes 10^{-19} \ J$.

The energy of an electron in the $3^{rd}$ orbit of $H$-atom (in $J$) is approximately:

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