સમીકરણ $\sin^{-1}x - \cos^{-1}x = \cos^{-1}\left(\frac{\sqrt{3}}{2}\right)$ માટે

  • A
    કોઈ ઉકેલ નથી
  • B
    અનન્ય ઉકેલ
  • C
    અસંખ્ય ઉકેલો
  • D
    આમાંથી કોઈ નહીં

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Similar Questions

${\tan ^{ - 1}}\left[ {\cos \left( {2\,{{\tan }^{ - 1}}\frac{3}{4}} \right)\, + \,\sin \,\left( {2\,{{\cot }^{ - 1}}\frac{1}{2}} \right)} \right]$ ની કિંમત શું છે?

$(\tan ^{-1} x)^2+(\cot ^{-1} x)^2=\frac{5 \pi^2}{8} \Rightarrow x=$

જો $\frac{\pi}{4} + \sum_{p=1}^{11} \tan^{-1} \left(\frac{2^{p-1}}{1+2^{2p-1}}\right) = \tan^{-1} \alpha$ હોય, તો $\tan \alpha$ ની કિંમત . . . . . . થાય.

જો $\sin ^{-1} x - \cos ^{-1} x = \frac{\pi}{6}$ હોય, તો $x$ ની કિંમત શોધો.

કિંમત શોધો: $\tan^{-1} \left( \frac{1}{\sqrt{x^2 - 1}} \right)$

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