The equation of the line passing through (2, | vedclass

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Question

(D) The equation of a line passing through a point $(x_1, y_1, z_1)$ with direction ratios $(a, b, c)$ is given by $\frac{x-x_1}{a} = \frac{y-y_1}{b}

Vedclass · Accepted Answer

$\frac{x-2}{0} = \frac{y-3}{1} = \frac{z-4}{0}$

Vedclass · Answer

(D) The equation of a line passing through a point $(x_1, y_1, z_1)$ with direction ratios $(a, b, c)$ is given by $\frac{x-x_1}{a} = \frac{y-y_1}{b} = \frac{z-z_1}{c}$.Given the point is $(2, 3, 4)$,so $x_1 = 2, y_1 = 3, z_1 = 4$.The line is parallel to the $Y$-axis. The direction ratios of the $Y$-axis are $(0, 1, 0)$.Therefore,the direction ratios of the line are $(a, b, c) = (0, 1, 0)$.Substituting these values into the equation,we get $\frac{x-2}{0} = \frac{y-3}{1} = \frac{z-4}{0}$.Thus,the correct option is $D$.

The equation of the line passing through $(2, 3, 4)$ and parallel to the $Y$-axis is . . . . . . .

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