The equations of the lines which cut off an i | vedclass

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(C) The equation of a line with slope $m$ and $y$-intercept $c$ is given by $y = mx + c$.Given that the $y$-intercept $c = -1$.Since the lines are equ

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$x - y - 1 = 0, x + y + 1 = 0$

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(C) The equation of a line with slope $m$ and $y$-intercept $c$ is given by $y = mx + c$.Given that the $y$-intercept $c = -1$.Since the lines are equally inclined to the axes,the angle of inclination $	heta$ is $45^{\circ}$ or $135^{\circ}$.Thus,the slope $m = 	an(45^{\circ}) = 1$ or $m = 	an(135^{\circ}) = -1$.Case $1$: For $m = 1$ and $c = -1$,the equation is $y = 1x - 1$,which simplifies to $x - y - 1 = 0$.Case $2$: For $m = -1$ and $c = -1$,the equation is $y = -1x - 1$,which simplifies to $x + y + 1 = 0$.Therefore,the required equations are $x - y - 1 = 0$ and $x + y + 1 = 0$.

The equations of the lines which cut off an intercept of $-1$ from the $y$-axis and are equally inclined to the axes are

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