The equivalent mass of a certain bivalent met | vedclass

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(A) The atomic weight of a metal is calculated as: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given that the metal is biv

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$111$

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(A) The atomic weight of a metal is calculated as: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given that the metal is bivalent,its valency is $2$.$	ext{Atomic weight} = 20 	imes 2 = 40 \ g \ mol^{-1}$.The molecular formula of the anhydrous chloride of a bivalent metal $M$ is $MCl_2$.The molecular mass of $MCl_2 = 	ext{Atomic mass of } M + 2 	imes 	ext{Atomic mass of } Cl$.$	ext{Molecular mass} = 40 + 2 	imes 35.5 = 40 + 71 = 111 \ g \ mol^{-1}$.

Column $-I$	Column $-II$
$(i)$ Barium sulphate	$(a)$ $1877 \ g/mol$
$(ii)$ Magnesium pyrophosphate	$(b)$ $235 \ g/mol$
$(iii)$ Ammonium phosphomolybdate	$(c)$ $188 \ g/mol$
$(iv)$ Silver chloride	$(d)$ $222 \ g/mol$
$(v)$ Silver bromide	$(e)$ $143.5 \ g/mol$
$(vi)$ Silver iodide	$(f)$ $233 \ g/mol$

The equivalent mass of a certain bivalent metal is $20$. The molecular mass of its anhydrous chloride is

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