The first and the last terms of an AP are 17 | vedclass

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(B) Given that,First term $a = 17$Last term $l = 350$Common difference $d = 9$Let there be $n$ terms in the $AP$.The formula for the $n^{th}$ term is

Vedclass · Accepted Answer

$6973$

Vedclass · Answer

(B) Given that,First term $a = 17$Last term $l = 350$Common difference $d = 9$Let there be $n$ terms in the $AP$.The formula for the $n^{th}$ term is $l = a + (n - 1)d$.Substituting the values: $350 = 17 + (n - 1)9$$333 = (n - 1)9$$n - 1 = 37$$n = 38$Now,the sum of $n$ terms is given by $S_n = \frac{n}{2}(a + l)$.$S_{38} = \frac{38}{2}(17 + 350)$$S_{38} = 19 	imes 367 = 6973$.Thus,there are $38$ terms and their sum is $6973$.

The first and the last terms of an $AP$ are $17$ and $350$ respectively. If the common difference is $9,$ how many terms are there and what is their sum?

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