The function f(x) = x^{2} + 2x - 5 is strictl | vedclass

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(A) Given function is $f(x) = x^{2} + 2x - 5$. To find the interval where the function is strictly increasing,we calculate the derivative $f'(x)$. $f'

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$(-1, \infty)$

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(A) Given function is $f(x) = x^{2} + 2x - 5$. To find the interval where the function is strictly increasing,we calculate the derivative $f'(x)$. $f'(x) = \frac{d}{dx}(x^{2} + 2x - 5) = 2x + 2$. For a function to be strictly increasing,we must have $f'(x) > 0$. $2x + 2 > 0$ $2x > -2$ $x > -1$. Thus,the function is strictly increasing in the interval $(-1, \infty)$.

The function $f(x) = x^{2} + 2x - 5$ is strictly increasing in the interval

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