The half-life period of a radioactive materia | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{45 \ min}{15 \ min} = 3$. The remaining amou

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(B) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{45 \ min}{15 \ min} = 3$. The remaining amount of radioactive material $N$ is given by the formula $N = N_o 	imes (\frac{1}{2})^n$. Assuming the initial amount $N_o = 100 \%$,the remaining amount is $N = 100 	imes (\frac{1}{2})^3 = \frac{100}{8} = 12.5 \%$. Thus,$12.5 \%$ of the radioactivity remains.

The half-life period of a radioactive material is $15 \ minutes$. What $\%$ of radioactivity of that material will remain after $45 \ minutes$?

Similar Questions

What is the order of radioactive decay of a substance?

$_{11}Na^{24}$ has a half-life of $15 \ h$. On heating,its half-life will:

If $1 \ \mu g$ of radium $(^{226}Ra)$ has disintegrated for $500$ years,how many alpha particles will be emitted per second?

$A$ radioactive element with half-life $6.5 \ hr$ has $48 \times 10^{19}$ atoms. Number of atoms left after $26 \ hr$ is:

The half-life of radium is $1580 \ yrs$. Its average life will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module