The Henry's law constant $(K_H)$ values of three gases $(A, B, C)$ in water are $145$,$2 \times 10^{-5}$,and $35$ kbar,respectively. The solubility of these gases in water follow the order:

  • A
    $B > C > A$
  • B
    $A > C > B$
  • C
    $A > B > C$
  • D
    $B > A > C$

Explore More

Similar Questions

Rank the following solvents in decreasing order of their ability to dissolve the given solute (naphthalene).

Assertion : When a salt such as $NaCl$ dissolves,the $Na^{+}$ and $Cl^{-}$ ions leaving the crystal lattice acquire far greater freedom.
Reason : In thermodynamic terms,the formation of solution occurs with a favourable change in free energy,i.e.,$\Delta H$ has a high positive value and $T\Delta S$ a low negative value.

For the solution of the gases $w$,$x$,$y$ and $z$ in water at $298 \ K$,the Henry's law constants $(K_H)$ are $0.5$,$2$,$35$ and $40 \ kbar$,respectively. The correct plot for the given data is

Henry's law constant for the molality of methane in benzene at $298 \, K$ is $4.27 \times 10^{5} \, mm \, Hg$. Calculate the solubility of methane in benzene at $298 \, K$ under $760 \, mm \, Hg$.

Assertion: $A$ mixture of $He$ and $O_2$ is used for respiration for deep sea divers.
Reason: $He$ is soluble in blood.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo