The image of the line x+y-2=0 in the y-axis i | vedclass

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(A) To find the image of the line $x+y-2=0$ in the $y$-axis,we replace $x$ with $-x$ in the equation of the line.Substituting $x = -x$ into $x+y-2=0$,

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$x-y+2=0$

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(A) To find the image of the line $x+y-2=0$ in the $y$-axis,we replace $x$ with $-x$ in the equation of the line.Substituting $x = -x$ into $x+y-2=0$,we get:$(-x)+y-2=0$$-x+y-2=0$Multiplying by $-1$,we get:$x-y+2=0$Alternatively,the line $x+y=2$ passes through points $A(2, 0)$ and $B(0, 2)$.The image of $A(2, 0)$ in the $y$-axis is $A'(-2, 0)$,and the image of $B(0, 2)$ is $B(0, 2)$ itself.The equation of the line passing through $A'(-2, 0)$ and $B(0, 2)$ is:$y-0 = \frac{2-0}{0-(-2)}(x-(-2))$$y = \frac{2}{2}(x+2)$$y = x+2$$x-y+2=0$

The image of the line $x+y-2=0$ in the $y$-axis is

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