The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal,when displacement (amplitude = $a$) is

$A$ particle of mass $10 \, g$ is describing $S.H.M.$ along a straight line with a period of $2 \, s$ and an amplitude of $10 \, cm$. Its kinetic energy when it is at $5 \, cm$ from its equilibrium position is

What is the displacement of a body in $SHM$ when the potential energy becomes three times its kinetic energy?

$A$ particle starts from the mean position and performs $S.H.M.$ with a period of $4 \ s$. At what time is its kinetic energy $50 \%$ of its total energy (in $s$)?

$A$ linear harmonic oscillator of force constant $2 \times 10^6 \, N/m$ and amplitude $0.01 \, m$ has a total mechanical energy of $160 \, J$. Its

The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure. The potential energy $U(x)$ versus time $t$ plot of the particle is correctly shown in figure: