The length of a square field is 50 , m. A cow | vedclass

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(D) Suppose the cow is tethered at the vertex $A$ of the square field $ABCD$ by a $3 \, m$ long rope.Since the angle at each vertex of a square is $90

Vedclass · Accepted Answer

$7.065$

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(D) Suppose the cow is tethered at the vertex $A$ of the square field $ABCD$ by a $3 \, m$ long rope.Since the angle at each vertex of a square is $90^{\circ}$,the area the cow can graze is a sector of a circle with radius $r = 3 \, m$ and central angle $	heta = 90^{\circ}$.Area of the sector $= \frac{\pi r^2 	heta}{360^{\circ}}$$= \frac{3.14 	imes (3)^2 	imes 90^{\circ}}{360^{\circ}}$$= \frac{3.14 	imes 9 	imes 1}{4}$$= \frac{28.26}{4}$$= 7.065 \, m^2$Thus,the area of the region in which the cow can graze is $7.065 \, m^2$.

The length of a square field is $50 \, m$. $A$ cow is tethered at one of the vertices by a $3 \, m$ long rope. Find the area of the region of the field in which the cow can graze. $(\pi = 3.14)$ (in $m^2$)

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