The length of an iron wire is L and the area | vedclass

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(C) The formula for Young's modulus $(Y)$ is given by $Y = \frac{	ext{Stress}}{	ext{Strain}} = \frac{F/A}{l/L} = \frac{FL}{Al}$.Rearranging this for

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Increase in length is inversely proportional to $A$.

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(C) The formula for Young's modulus $(Y)$ is given by $Y = \frac{	ext{Stress}}{	ext{Strain}} = \frac{F/A}{l/L} = \frac{FL}{Al}$.Rearranging this formula to solve for the increase in length $(l)$,we get:$l = \frac{FL}{YA}$.From this expression,it is clear that the increase in length $(l)$ is directly proportional to the force $(F)$ and the original length $(L)$,and inversely proportional to the Young's modulus $(Y)$ and the area of cross-section $(A)$.Therefore,$l \propto \frac{1}{A}$.Thus,the correct statement is that the increase in length is inversely proportional to $A$.

The length of an iron wire is $L$ and the area of cross-section is $A$. The increase in length is $l$ upon applying a force $F$ on its two ends. Which of the following statements is correct?

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