The locus of a point such that the sum of its | vedclass

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(C) Let $P(x, y)$ be any point on the locus. According to the problem,the sum of the distances from $P$ to $F_1(0, 2)$ and $F_2(0, -2)$ is $6$.$\sqrt{

Vedclass · Accepted Answer

$9x^2 + 5y^2 = 45$

Vedclass · Answer

(C) Let $P(x, y)$ be any point on the locus. According to the problem,the sum of the distances from $P$ to $F_1(0, 2)$ and $F_2(0, -2)$ is $6$.$\sqrt{x^2 + (y - 2)^2} + \sqrt{x^2 + (y + 2)^2} = 6$$\sqrt{x^2 + (y - 2)^2} = 6 - \sqrt{x^2 + (y + 2)^2}$Squaring both sides:$x^2 + (y - 2)^2 = 36 + x^2 + (y + 2)^2 - 12\sqrt{x^2 + (y + 2)^2}$$x^2 + y^2 - 4y + 4 = 36 + x^2 + y^2 + 4y + 4 - 12\sqrt{x^2 + (y + 2)^2}$$-8y - 36 = -12\sqrt{x^2 + (y + 2)^2}$$2y + 9 = 3\sqrt{x^2 + (y + 2)^2}$Squaring again:$(2y + 9)^2 = 9(x^2 + y^2 + 4y + 4)$$4y^2 + 36y + 81 = 9x^2 + 9y^2 + 36y + 36$$9x^2 + 5y^2 = 45$

The locus of a point such that the sum of its distances from the points $(0, 2)$ and $(0, -2)$ is $6$,is

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