The logical statement $\sim(p \vee q) \vee(\sim p \wedge q)$ is equivalent to

Let $p, q$ and $r$ be the statements:
$p$: $X$ is an equilateral triangle
$q$: $X$ is an isosceles triangle
$r: q \vee \sim p$
Then the equivalent statement of $r$ is:

Which one of the following statements is not a tautology?

Given $p$: $A$ man is a judge,$q$: $A$ man is honest. If $S_1$: If a man is a judge,then he is honest; $S_2$: If a man is a judge,then he is not honest; $S_3$: $A$ man is not a judge or he is honest; $S_4$: $A$ man is a judge and he is honest. Then:

The statement pattern $(p \wedge q) \vee (\sim p \wedge q) \vee (r \wedge \sim q)$ is logically equivalent to:

Let $p$ be the statement '$x$ is an irrational number',$q$ be the statement '$y$ is a transcendental number',and $r$ be the statement '$x$ is a rational number or $y$ is a transcendental number'.
Statement-$1$: $r$ is equivalent to $q \lor p$.
Statement-$2$: $r$ is equivalent to $(p \Leftrightarrow \sim q)$.