The magnetic moment of $[NiX_4]^{2-}$ ion is found to be zero. Then the ion is : ($X =$ monodentate anionic ligand)
- A$sp^3$ hybridised
- B$spd^2$ hybridised
- C$dsp^2$ hybridised
- D$d^2sp$ hybridised
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Similar Questions
What type of geometry and magnetic nature is present in the complex $[NiCl_4]^{2-}$?
Identify the complex having the highest number of unpaired electrons from the following:
DifficultMHT CET 2026
View SolutionMatch List-$I$ with List-$II$:
List-$I$ (Complex/ion) List-$II$ (Shape/geometry) $A$. $[Pt(Cl)_2(NH_3)_2]$ $I$. Octahedral $B$. $[Co(NH_3)_6]Cl_3$ $II$. Trigonal bipyramidal $C$. $[NiCl_4]^{2-}$ $III$. Square planar $D$. $[Fe(CO)_5]$ $IV$. Tetrahedral
| List-$I$ (Complex/ion) | List-$II$ (Shape/geometry) |
| $A$. $[Pt(Cl)_2(NH_3)_2]$ | $I$. Octahedral |
| $B$. $[Co(NH_3)_6]Cl_3$ | $II$. Trigonal bipyramidal |
| $C$. $[NiCl_4]^{2-}$ | $III$. Square planar |
| $D$. $[Fe(CO)_5]$ | $IV$. Tetrahedral |
MediumNEET 2026
View SolutionIdentify the hybridization of the central metal atom in the $[Fe(CO)_5]$ complex.
Which of the following statements is correct with respect to $[Mn(CN)_6]^{3-}$?
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