The major product (A) formed in the reaction | vedclass

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(B) The given reaction involves a primary alkyl halide with a bulky group (phenyl) attached to the $\beta$-carbon,reacting with a strong base/nucleoph

Vedclass · Accepted Answer

$CH_3-CH_2-C(C_6H_5)=CH_2$

Vedclass · Answer

(B) The given reaction involves a primary alkyl halide with a bulky group (phenyl) attached to the $\beta$-carbon,reacting with a strong base/nucleophile $(CH_3O^-)$ in a protic solvent $(CH_3OH)$.This reaction proceeds via an $E2$ elimination mechanism.The methoxide ion $(CH_3O^-)$ acts as a base and abstracts a proton from the $\beta$-carbon (the carbon attached to the phenyl group),leading to the formation of a double bond between the $\alpha$ and $\beta$ carbons.The major product formed is $2$-phenylbut-$1$-ene,which is $CH_3-CH_2-C(C_6H_5)=CH_2$.

The major product $(A)$ formed in the reaction given below is:

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