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(B) The reaction is a dehydrohalogenation reaction using a base $(NaOCH_3)$.The nitro group $(-NO_2)$ is a strong electron-withdrawing group,which inc

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$3-chloro-2-methyl-5-nitrocyclopent-1-ene$

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(B) The reaction is a dehydrohalogenation reaction using a base $(NaOCH_3)$.The nitro group $(-NO_2)$ is a strong electron-withdrawing group,which increases the acidity of the hydrogen atom on the carbon bearing the nitro group.Under the influence of the base,the proton adjacent to the nitro group is removed,leading to the elimination of $HCl$ and the formation of a $C=C$ double bond in conjugation with the nitro group.Therefore,the major product is $3-chloro-2-methyl-5-nitrocyclopent-1-ene$ (as shown in the provided figure $2$).

The major product formed in the following reaction is
$1,2-dichloro-3-methyl-5-nitrocyclopentane$ $\xrightarrow[{Heat}]{{NaOCH_3(1 \ eq.)}}$ ?

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The major product formed in the following reaction is$1,2-dichloro-3-methyl-5-nitrocyclopentane$ $\xrightarrow[{Heat}]{{NaOCH_3(1 \ eq.)}}$ ?