The major products '$A$' and '$B$',respectively,are

  • A
    $H_3C-C(CH_3)_2-OSO_3H$ & $CH_3-C(CH_3)=CH-C(CH_3)_3$
  • B
    $CH_3-C(CH_3)=CH-C(CH_3)_3$ & $H_3C-C(CH_3)_2-OSO_3H$
  • C
    $CH_3-CH(CH_3)-CH_2-CH_2-CH(CH_3)-CH_3$ & $H_3C-C(CH_3)_2-OSO_3H$
  • D
    $H_3C-C(CH_3)_2-OSO_3H$ & $CH_3-CH(CH_3)-CH_2-CH_2-CH(CH_3)-CH_3$

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Similar Questions

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R.$
Assertion $A :$ Treatment of bromine water with propene yields $1-$bromopropan$-2-$ol.
Reason $R:$ Attack of water on bromonium ion follows Markovnikov rule and results in $1-$bromopropan$-2-$ol.
In the light of the above statements,choose the most appropriate answer from the options given below:

Ozonolysis of which olefin yields $CH_3CH_2CHO$ and $CH_3CHO$?

The product $A$ of the following reaction is:
$R_2C=CHR' \xrightarrow[Zn/H_2O]{O_3} A$

In the reaction with $HCl$,an alkene reacts in accordance with Markovnikov's rule to give the product $1-$chloro$-1-$methylcyclohexane. The possible alkene is:

Difficult
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The compound that will react most readily with gaseous bromine has the formula

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