The marks obtained (out of $100$) by a class of $80$ students are given below:
MarksNumber of students
$10-20$$6$
$20-30$$17$
$30-50$$15$
$50-70$$16$
$70-100$$26$

Construct a histogram to represent the data above.

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(N/A) Here,the class intervals are of unequal width. So,we shall compute the adjusted frequencies of each class. The minimum class size is $20-10=10$. The adjusted frequencies are computed by using the following formula:
$\text{Adjusted frequency} = \frac{\text{Minimum class size}}{\text{Class size}} \times \text{Frequency of the class}$
The adjusted frequencies are computed in the following table:
MarksNumber of students (Frequency)Adjusted Frequency
$10-20$$6$$\frac{10}{10} \times 6 = 6$
$20-30$$17$$\frac{10}{10} \times 17 = 17$
$30-50$$15$$\frac{10}{20} \times 15 = 7.5$
$50-70$$16$$\frac{10}{20} \times 16 = 8$
$70-100$$26$$\frac{10}{30} \times 26 \approx 8.67$

Now,we construct rectangles with class limits as bases and respective adjusted frequencies as heights.

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The mean of natural numbers between $1$ to $20$ which are multiples of $3$ is ..........

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