The maximum value of $a.c.$ voltage in a circuit is $707 \ V$. Its $rms$ value is.....$V$

$A$ standard filament lamp consumes $100\,W$ when connected to $200\,V$ $AC$ mains supply. The peak current through the bulb will be $........\,A$.

The instantaneous values of current and voltage in an $AC$ circuit are given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$ and $V = 5 \sin(100 \pi t - \frac{\pi}{4})$. Then,

If $i = t^2$ for $0 < t < T$,then the $r.m.s.$ value of the current is:

The mean and $rms$ value of an alternating voltage for a half cycle,as shown in the figure,are respectively:

The frequency of an alternating current is $ 50 \,Hz $. What is the minimum time taken by the current to reach its peak value from its $ rms $ value?