The mean and variance of a binomial distribution are $6$ and $4$. The parameter $n$ is

Let $9$ distinct balls be distributed among $4$ boxes,$B_{1}, B_{2}, B_{3}$ and $B_{4}$. If the probability that $B_{3}$ contains exactly $3$ balls is $k\left(\frac{3}{4}\right)^{9}$,then $k$ lies in the set:

The mean and standard deviation of a binomial variate $X$ are $4$ and $\sqrt{3}$ respectively. Then $P(X \geq 1)$ is equal to

$A$ bag consists of $10$ balls each marked with one of the digits $0$ to $9$. If four balls are drawn successively with replacement from the bag,what is the probability that none is marked with the digit $0$?

The probability that a bomb will hit the target is $0.8$. Out of $6$ bombs dropped, what is the probability that at least $1$ will miss the target?

The mean of a binomial variate $X \sim B(n, p)$ is $1$. If $n > 2$ and $P(X=2)=\frac{27}{128}$, then the variance of the distribution is