The median class in the following frequency d | vedclass

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Question

(A) First,calculate the cumulative frequency $(cf)$ for each class:- $20-25$: $cf = 2$- $25-30$: $cf = 2 + 5 = 7$- $30-35$: $cf = 7 + 8 = 15$- $35-40$

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$35-40$

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(A) First,calculate the cumulative frequency $(cf)$ for each class:- $20-25$: $cf = 2$- $25-30$: $cf = 2 + 5 = 7$- $30-35$: $cf = 7 + 8 = 15$- $35-40$: $cf = 15 + 10 = 25$- $40-45$: $cf = 25 + 7 = 32$- $45-50$: $cf = 32 + 10 = 42$- $50-55$: $cf = 42 + 3 = 45$The total frequency $n = 45$.We need to find $\frac{n}{2} = \frac{45}{2} = 22.5$.The median class is the class whose cumulative frequency is just greater than $22.5$.Looking at the cumulative frequencies,$25$ is the first value greater than $22.5$,which corresponds to the class interval $35-40$.Therefore,the median class is $35-40$.

Class	$20-25$	$25-30$	$30-35$	$35-40$	$40-45$	$45-50$	$50-55$
Frequency	$2$	$5$	$8$	$10$	$7$	$10$	$3$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$7$	$12$	$x$	$28$	$y$	$9$

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$43$	$55$	$37$	$18$

The median class in the following frequency distribution is ..........

Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$

Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$

Similar Questions

Midpoint (Midvalue) of the class $15-30$ is ........

The mode of the following data is $33 \frac{1}{3}$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Frequency $7$ $12$ $x$ $28$ $y$ $9$

The formula to find the mean of an ungrouped data is ........

Find the mode of the following frequency distribution:

Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$

Frequency $8$ $12$ $27$ $43$ $55$ $37$ $18$

$\sum_{i=1}^{10} (x_i - \bar{x}) = \dots$

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The median class in the following frequency distribution is .......... Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$