The mid-point of the line segment joining the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The mid-point formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\

Vedclass · Accepted Answer

$(-4, 2)$

Vedclass · Answer

(B) The mid-point formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$.Given points are $A(-2, 8)$ and $B(-6, -4)$.Substituting the values into the formula:Mid-point $= \left(\frac{-2 + (-6)}{2}, \frac{8 + (-4)}{2}\right)$Mid-point $= \left(\frac{-8}{2}, \frac{4}{2}\right)$Mid-point $= (-4, 2)$.

The mid-point of the line segment joining the points $A(-2, 8)$ and $B(-6, -4)$ is

Similar Questions

The distance between $A(\cos \theta, 0)$ and $B(0, \sin \theta)$ is ...........

Find the area of a quadrilateral having the vertices $(-1, -1), (-4, -2), (-5, -4),$ and $(-2, -3)$.

The line segment joining $(0,0)$ and $(6,6)$ is divided into four congruent parts. Which of the following is one of the dividing points?

Find the circumcentre of the triangle with vertices $A(1, 2)$,$B(-2, 2)$,and $C(1, 5)$.

If $A(-1, 4), B(2, 3)$ and $C(8, 1)$,then which of the following is true regarding the collinearity of points $A, B,$ and $C$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module