The negation of sim s vee (sim r wedge s) is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the given expression be $P = \sim s \vee (\sim r \wedge s)$.We want to find the negation $\sim P = \sim (\sim s \vee (\sim r \wedge s))$.Using

Vedclass · Accepted Answer

$s \wedge r$

Vedclass · Answer

(A) Let the given expression be $P = \sim s \vee (\sim r \wedge s)$.We want to find the negation $\sim P = \sim (\sim s \vee (\sim r \wedge s))$.Using De Morgan's Law,$\sim (A \vee B) = \sim A \wedge \sim B$,we get:$\sim P = \sim (\sim s) \wedge \sim (\sim r \wedge s)$.This simplifies to $s \wedge (\sim (\sim r) \vee \sim s)$ by applying De Morgan's Law again.So,$\sim P = s \wedge (r \vee \sim s)$.Using the Distributive Law,$A \wedge (B \vee C) = (A \wedge B) \vee (A \wedge C)$,we get:$\sim P = (s \wedge r) \vee (s \wedge \sim s)$.Since $(s \wedge \sim s)$ is a contradiction (False),we have:$\sim P = (s \wedge r) \vee F = s \wedge r$.

The negation of $\sim s \vee (\sim r \wedge s)$ is equivalent to :

Similar Questions

The dual of $\left(x^{\prime} \vee y^{\prime}\right) = x \wedge y$ is

$(p \wedge \sim q \wedge \sim r) \vee (\sim p \wedge q \wedge \sim r) \vee (\sim p \wedge \sim q \wedge r)$ is equivalent to-

For each of the following statements,determine whether an inclusive "Or" or exclusive "Or" is used. Give reasons for your answer.
To enter a country,you need a passport or a voter registration card.

The logical equivalent of $p \Leftrightarrow q$ is :-

Which of the following is a statement?

Vedclass Test Series

Exam Paper Generator

Online Exam Module