The number of anti-bonding electrons present | vedclass

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(D) The total number of electrons in $O_{2}^{-}$ is $8 + 8 + 1 = 17$.The molecular orbital configuration of $O_{2}^{-}$ is: $\sigma 1s^{2}, \sigma^{*}

Vedclass · Accepted Answer

$7$

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(D) The total number of electrons in $O_{2}^{-}$ is $8 + 8 + 1 = 17$.The molecular orbital configuration of $O_{2}^{-}$ is: $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} = \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{2} = \pi^{*} 2p_{y}^{1}$.Anti-bonding electrons are those in orbitals denoted with an asterisk $(*)$.Number of anti-bonding electrons $= 2(\sigma^{*} 1s) + 2(\sigma^{*} 2s) + 2(\pi^{*} 2p_{x}) + 1(\pi^{*} 2p_{y}) = 7$.

The number of anti-bonding electrons present in $O_{2}^{-}$ molecular ion is

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