The number of compounds from the following wh | vedclass

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(B) The Hoffmann bromamide degradation reaction $(Br_2/KOH)$ is specific to primary amides $(R-CONH_2)$, converting them into primary amines $(R-NH_2)

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The Hoffmann bromamide degradation reaction $(Br_2/KOH)$ is specific to primary amides $(R-CONH_2)$, converting them into primary amines $(R-NH_2)$.Gabriel phthalimide synthesis is also used for the preparation of primary amines $(R-NH_2)$ from primary alkyl halides $(R-X)$.Therefore, we need to identify the number of primary amides $(R-CONH_2)$ in the given set.Let's analyze the structures provided in the image:$1$. $C_6H_5CONH_2$ (Benzamide) - Primary amide.$2$. $C_6H_5CH_2CONH_2$ ($2$-Phenylacetamide) - Primary amide.$3$. $CH_3CONH_2$ (Acetamide) - Primary amide.$4$. $C_6H_{11}CONHCH_2CH_3$ - Secondary amide (Does not undergo Hoffmann degradation).$5$. $(CH_3)_3CCONHCH_3$ - Secondary amide (Does not undergo Hoffmann degradation).$6$. $C_6H_{11}CONH_2$ (Cyclohexanecarboxamide) - Primary amide.Counting the primary amides, we have compounds $1$, $2$, $3$, and $6$.Thus, there are $4$ such compounds.

The number of compounds from the following which can undergo reaction with $Br_2/KOH$ (alcoholic) to give respective products, and these respective products can also be obtained separately by the Gabriel phthalimide synthesis, is:

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