The output Y of the following digital logic c | vedclass

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Question

(D) The given circuit consists of a $NOT$ gate, an $AND$ gate, and an $OR$ gate. From the circuit diagram, the output of the $NOT$ gate is $\bar{A}$.

Vedclass · Accepted Answer

$A = 1, B = 1, C = 1$

Vedclass · Answer

(D) The given circuit consists of a $NOT$ gate, an $AND$ gate, and an $OR$ gate. From the circuit diagram, the output of the $NOT$ gate is $\bar{A}$. The output of the $AND$ gate is $B \cdot C$. These two outputs are fed into an $OR$ gate, so the final output $Y$ is given by the Boolean expression: $Y = \bar{A} + (B \cdot C)$. We want to find the inputs for which $Y = 1$. Let's test the options: $(A)$ $A = 1, B = 0, C = 0$: $Y = \bar{1} + (0 \cdot 0) = 0 + 0 = 0$. $(B)$ $A = 1, B = 0, C = 1$: $Y = \bar{1} + (0 \cdot 1) = 0 + 0 = 0$. $(C)$ $A = 1, B = 1, C = 0$: $Y = \bar{1} + (1 \cdot 0) = 0 + 0 = 0$. $(D)$ $A = 1, B = 1, C = 1$: $Y = \bar{1} + (1 \cdot 1) = 0 + 1 = 1$. Thus, for the inputs $A = 1, B = 1, C = 1$, the output $Y$ is $1$.

The output $Y$ of the following digital logic circuit will be '$1$' (one) for the inputs:

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