The power of two convex lenses A and B are 8 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnifying power $m$ of a simple microscope is given by the formula $m = 1 + \frac{D}{f}$,where $D$ is the least distance of distinct vision $

Vedclass · Accepted Answer

$A$ will be greater than $B$

Vedclass · Answer

(B) The magnifying power $m$ of a simple microscope is given by the formula $m = 1 + \frac{D}{f}$,where $D$ is the least distance of distinct vision $(25 \ cm)$ and $f$ is the focal length of the lens.Since power $P = \frac{1}{f}$ (in meters),we can write the formula as $m = 1 + D \cdot P$.For lens $A$,$P_A = 8 \ D$,so $m_A = 1 + 0.25 	imes 8 = 1 + 2 = 3$.For lens $B$,$P_B = 4 \ D$,so $m_B = 1 + 0.25 	imes 4 = 1 + 1 = 2$.Since $m_A > m_B$,the magnification of lens $A$ will be greater than that of lens $B$.

The power of two convex lenses $A$ and $B$ are $8$ diopters and $4$ diopters respectively. If they are to be used as a simple microscope,the magnification of

Similar Questions

The intermediate image formed by the objective of a compound microscope is

The length of the compound microscope is $14 \, cm$. The magnifying power for a relaxed eye is $25$. If the focal length of the eye lens is $5 \, cm$,then the object distance for the objective lens will be.......$ cm$.

In a compound microscope,the objective of focal length ${f_o}$ and the eyepiece of focal length ${f_e}$ are placed at a distance $L$ such that $L$ equals:

$A$ simple microscope is used to see an object first in blue light and then in red light. Due to the change from blue to red light, what is the effect on its magnifying power?

In a Ramsden eyepiece,two planoconvex lenses,each of focal length $f$,are separated by a distance of $12 \ cm$. The equivalent focal length (in $cm$) of the eyepiece is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module