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(D) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols but does not reduce

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(D) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols but does not reduce esters,carboxylic acids,or amides under normal conditions. In the given substrate,there is a ketone group and an ester group $(-COOCH_3)$. Therefore,$NaBH_4$ will selectively reduce the ketone group to a secondary alcohol $(-CHOH)$ while leaving the ester group unaffected. The final product is a cyclohexane ring with an $-OH$ group,a $-CH_2-COOCH_3$ group,and a $-CH_3$ group.

The product formed in the following chemical reaction is :

Similar Questions

The major product of the following reaction is:

The reaction of benzoic acid with methanol in the presence of an acid catalyst $(H^+)$ is shown below. Identify the correct product.
$C_6H_5COOH + CH_3O^{18}H \xrightarrow{H^+} \text{Product}$

When salicylic acid is treated with acetic anhydride,we get:

Assertion : Nitration of benzoic acid gives $m-$nitrobenzoic acid.
Reason : Carboxyl group increases the electron density at meta-position.

The most acidic carboxylic acid is

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