The ratio of momenta of an electron and an al | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The momentum $p$ of a charged particle accelerated from rest through a potential difference $V$ is given by the relation $p = \sqrt{2mqV}$,where $

Vedclass · Accepted Answer

$\sqrt{\frac{m_{e}}{2 m_{\alpha}}}$

Vedclass · Answer

(D) The momentum $p$ of a charged particle accelerated from rest through a potential difference $V$ is given by the relation $p = \sqrt{2mqV}$,where $m$ is the mass and $q$ is the charge of the particle.For an electron,$m = m_{e}$ and $q = e$.For an $\alpha$-particle,$m = m_{\alpha}$ and $q = 2e$.Taking the ratio of the momenta:$\frac{p_{e}}{p_{\alpha}} = \frac{\sqrt{2 m_{e} e V}}{\sqrt{2 m_{\alpha} (2e) V}}$$\frac{p_{e}}{p_{\alpha}} = \sqrt{\frac{2 m_{e} e V}{4 m_{\alpha} e V}}$$\frac{p_{e}}{p_{\alpha}} = \sqrt{\frac{m_{e}}{2 m_{\alpha}}}$

The ratio of momenta of an electron and an $\alpha$-particle which are accelerated from rest by a potential difference of $100 \ V$ is

Similar Questions

The velocity of a particle $A$ is $3$ times the velocity of a proton. If the ratio of the de Broglie wavelengths of the particle $A$ and the proton is $3:2$,the mass of the particle $A$ is (where $m_{p}$ is the mass of the proton).

$A$ proton,an electron,and an alpha particle have the same kinetic energies. Their de-Broglie wavelengths will be compared as:

The graph which shows the variation of $\left(\frac{1}{\lambda^2}\right)$ and its kinetic energy,$E$ is (where $\lambda$ is de Broglie wavelength of a free particle):

Which of the following has the largest de Broglie wavelength?

Vedclass Test Series

Exam Paper Generator

Online Exam Module