The ratio of specific heats left(frac{C_{P}}{ | vedclass

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(B) The molar heat capacity at constant volume is given by $C_{V} = \frac{fR}{2}$,where $f$ is the degree of freedom and $R$ is the universal gas cons

Vedclass · Accepted Answer

$1+\frac{2}{f}$

Vedclass · Answer

(B) The molar heat capacity at constant volume is given by $C_{V} = \frac{fR}{2}$,where $f$ is the degree of freedom and $R$ is the universal gas constant.The molar heat capacity at constant pressure is given by Mayer's relation: $C_{P} = C_{V} + R$.Substituting the value of $C_{V}$,we get $C_{P} = \frac{fR}{2} + R = R\left(1 + \frac{f}{2}\right) = R\left(\frac{f+2}{2}\right)$.The ratio of specific heats $\gamma = \frac{C_{P}}{C_{V}}$ is calculated as:$\gamma = \frac{R\left(\frac{f+2}{2}\right)}{\frac{fR}{2}} = \frac{f+2}{f} = 1 + \frac{2}{f}$.

The ratio of specific heats $\left(\frac{C_{P}}{C_{V}}\right)$ in terms of degree of freedom $(f)$ is given by

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