The reaction of Benzenediazonium chloride with aniline yields a yellow dye. The name of the yellow dye is

$A$ student has been given a compound $x$ of molecular formula $C_6H_7N$. $x$ is sparingly soluble in water. However, on addition of dilute mineral acid, $x$ becomes soluble in water. $x$ when treated with $CHCl_3$ and $KOH$ (alc.) produces $y$. $y$ has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, $x$ gives a compound $z$ which is soluble in alkali. The number of different $H$ atoms present in $z$ is:

Which of the following statements is incorrect?

Identify the correct statements:
$(A)$ Primary amines do not give diazonium salts when treated with $NaNO_2$ in acidic conditions.
$(B)$ Aliphatic and aromatic primary amines on heating with $CHCl_3$ and ethanolic $KOH$ form carbylamines.
$(C)$ Secondary and tertiary amines also give the carbylamine test.
$(D)$ Benzenesulfonyl chloride is known as Hinsberg's reagent.
$(E)$ Tertiary amines react with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below:

In the above conversion of compound $(X)$ to product $(Y)$,the sequence of reagents to be used will be:

The decreasing order of basicity is:
$(1) \ CH_3CONH_2$
$(2) \ CH_3CH_2NH_2$
$(3) \ PhCH_2CONH_2$